A compound of P and S contains 27.87% P and 72.13% S. The molar mass of the compound is 223.3 g/mol. Calculate its molecular formula.
2007-01-21 11:09:05 · 2 answers · asked by Joann 2 in Science & Mathematics ➔ Chemistry
atomic mass unit (amu) of P = 30.973762
amu of S = 32.065
Assume the compound >> PxSy
Givens:
30.973762x + 32.065y = 223.3 ... ... (1)
(30.973762x) / (32.065y) = (27.87%) / (72.13%)
Separating x and y
x/y = (0.2787/0.7213) x (32.065/30.973762) = 0.39998 >> 0.4
x/y = 2/5
Soooo
<
2007-01-21 11:48:38 · answer #1 · answered by Sheen 4 · 1⤊ 0⤋
It doesn't matter what the molecular weight is
If it contains 27.87% phosphorus and 72.13% sulpher It has to either be PS or a mixture of dry chemical 27.87% phosporus and 72.13% sulpher because your percentages add up to 100%
2007-01-21 11:21:23 · answer #2 · answered by bob shark 7 · 0⤊ 1⤋