2007-01-21 11:00:39 · 6 answers · asked by stephen m 1 in Games & Recreation ➔ Other - Games & Recreation
Same time, they both drop at same terminal velocity, they both increase 32 feet per second
2007-01-21 11:03:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋
All this crap about terminal velocity is all well and good, but in the real world wind resistance will have an impact on the balls.
I would probably guess that bowling ball would land first, since it is heavier and smoother. A baseball has stitching on it and is lighter, it will therefore more likely be affected by wind resistance which may prevent it from hitting terminal velocity or at least reduce the acceleration a little.
2007-01-21 11:15:06 · answer #2 · answered by ZCT 7 · 0⤊ 0⤋
the bowling ball is heavier but has a bigger surface area therefore they would drop at the same rate and they would both end up on the ground at the same time
2007-01-25 08:11:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the bowling ball loses do to the air friction coefficient and surface area. assume a vacuum and both would fall at the same rate.
2007-01-21 11:14:42 · answer #4 · answered by ben e 3 · 0⤊ 0⤋
The bowling ball, being the heavier one, would be the logical answer to that question.
2007-01-21 11:09:00 · answer #5 · answered by Richard H 7 · 0⤊ 0⤋
They will land at the same time, since both accelerate at the same rate (9.81 m/s^2)
2007-01-21 11:06:25 · answer #6 · answered by John H 4 · 0⤊ 0⤋