Okey - I need to calculate the equilibrium constant for a reaction with the following data: dH0 = -908kJ, dS0 = 181J/K, dG0 = -961.9kJ. Any takers? dG0 is at 298K and changes to 1098K. Assume dH and dS are constant over the temp difference. Query 2: Given: H2O(g) + Cl2O(g) 2 HOCl(g) K298 = 0.090, dH0 = 0, dS0 = -20, and J/K dG0 = 5.97 kJ/mol. For Cl2O(g): dG°f = 97.9 kJ/mol dH°f = 80.3 kJ/mol S° = 266.1 J/Kmol. Find the enthalpy of formation for HOCl. Please explain how you do both/either of these! Thanks in advance!
2007-01-21
09:40:55
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2 answers
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asked by
emsviper
2
in
Science & Mathematics
➔ Chemistry