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Can anyone do it?

2007-01-21 09:24:22 · 1 answers · asked by Z0LA 1 in Science & Mathematics Mathematics

1 answers

Integrate ∫sinh²x dx.

Remember the identities.

2sinh²x = cosh(2x) - 1
sinh(2x) = 2(sinh x)(cosh x)

∫sinh²x dx = ½∫(cosh(2x) - 1)dx = ½(½sinh(2x) - x) + C
= ½{(sinh x)(cosh x) - x} + C

2007-01-21 10:29:17 · answer #1 · answered by Northstar 7 · 0 0

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