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Find an equation of the parabola with focus (0,-1/8) and directix y=1/8

2007-01-21 08:44:32 · 1 answers · asked by Kevin P 1 in Science & Mathematics Mathematics

1 answers

Take a point(x,y)
Its distance to the focus squared is d= x^2 +(y+1/8)^2

Its distance to the directrix squared is (y-1/8)^2
By def. both should be equal

x^2 +y^2 +y/4 +1/64 = y^2 - y /4+1/64


x^2= -y/2 ===>y =-2x^2

2007-01-21 08:55:21 · answer #1 · answered by santmann2002 7 · 1 0

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