B = (4X^2+7X-3)/((x-2)(x+1)) - 3(x+1)/(x-2) - 2/(x+1)?

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B = (4X^2+7X-3)/((x-2)(x+1)) - 3(x+1)/(x-2) - 2/(x+1)?

Solve for B

B = (4X^2+7X-3)/((x-2)(x+1)) - 3(x+1)/(x-2) - 2/(x+1)

2007-01-21 08:34:34 · 3 answers · asked by A H 1 in Science & Mathematics ➔ Mathematics

3 answers

First, get all the fractions to have like denominators. To do this, multiply the second fraction by (x+1)/(x+1). Then multiply the last fraction by (x-2)/(x-2).

Once that is done, multiply out and simplify the numerator.

I ended up getting the numerator and the denominator to be equal terms, so B = 1.

2007-01-21 08:41:40 · answer #1 · answered by Master of All He Surveys 2 · 0⤊ 0⤋

B(x+1)(x-2) = (4x^2+7x-3) - 3(x^2+2x+1) - 2(x-2)
B(x+1)(x-2) = x^2-x-2 = (x-2)(x+1)
so B = 1

2007-01-21 08:52:57 · answer #2 · answered by ? 7 · 0⤊ 0⤋

What does ^ mean again?

2007-01-21 08:42:08 · answer #3 · answered by betty_htch 5 · 0⤊ 0⤋