Math Equation?

Question

2 Equations, 5 Variables
c and (q2) are constants
a,b>0
c is an element of (0,a)

1) a-2b(Q1)-(Q2)-c
2) a-2b(Q2)-(Q1)-c

Solved for Q1 = a-2b(Q2)-c

Inserted into eqation 1:

a-2b[Q1]-(Q2)-c

a-2b[a-2b(Q2)-c]-(Q2)-c

QUESTION: Now solve for Q2
Then solve for Q1

Any help would be appreciated

Answer 1

If c and Q2 are constants then the variables seem to be a, b, and Q2. That's just three variables.

But neither 1) or 2) are equations; they are expressions. To have an equation, you must state an equality between two expressions.

If you intended to say that expressions are both = 0, then you would have two equations in three unknowns.

Three equations are required to solve a system of three unknowns; therefore a solution is not possible.

By the way, if Q2 and c are both constants, then you can replace them by C= Q2-c