i need the Least common factors 4 the following 3 problems, 24&40,:36,&72, and 28&42. thanx!?

Question

I NEED THE ANSWERS QUICKLY! BY THA END OF 2DAY!

Answer 1

I dont know if what I wrote is exactly what you're asking for, but here they are...

24,40 >>> 120 (you divide them by 2,2,2,3,5)
36,72 >>> 72 (2,2,2,3,3)
28,42 >>> 84 (2,2,3,7)

(the result is the product of these numbers)

Answer 2

LCF(24&40) = 8
M(24) = {1, 2, 3, 4, 6, 8, 12, 24}
M(40) = {1, 2, 4, 5, 8, 10, 20, 40
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LCF(36&72) = 36
M(36) = {1, 2, 3, 4, 6, 9, 12, 18, 36}
M(72) = {1, 2, 3, 4, 6, 8, 9, 12, 18, 36, 72}
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LCF(28&42) = 14
M(28) = {1, 2, 4, 7, 14, 28}
M(42) ={1, 2, 3, 6, 7, 14, 21, 42}
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Answer 3

24=2^3*3 IIIIII 40=2^3*5 LCF = 2^3 *3*5 =120

36= 2^2*3^2 IIIII 72=2^3 *3^2 IIIIIII LCF = 2^3*3^2 =72

28=2^2*7 III 42 =2*3*7 IIII LCF = 2^2*3*7 =84

Answer 4

24 & 40
common factor 8
3 & 5

36 & 72
common factor 36
1 & 2

28 & 42
common factor 14
2 & 3

Answer 5

I am assuming that you mean a common factor other than 1.

24 and 40
Both are even numbers, so both have a factor of 2. You can't get much smaller than that, so the least common factor is 2.

36 and 72
Again, both are even numbers, so both have a factor of 2. Can't go smaller, so the least common factor is 2.

28 and 42
Again, both are even numbers. Least common factor is 2.

Answer 6

1. 8

2. 9

3. 2

Answer 7

24=2x2x2x3
40=2x2x2x5

36=2x2x3x3
72=2x2x2x3x3

28=2x2x7
42=2x3x7