mass in grams of 3.52 mol of chromium(III) sulfate decahydrate
could you please explain it step by step
2007-01-21 07:01:42 · 2 answers · asked by stardust6547 2 in Science & Mathematics ➔ Chemistry
Cr (SO4)3 (H2O)10 is what you have.
you can break it down to the indivudual components, and look it up ot the periodic table of elements for the molecular mass, add it all together and then multiply by your 3.52 mol quantity.
Chromium: Atomic mass 51.9961 g·mol−1
Sulfur: Atomic mass 32.065 g·mol−1
Oxygen: Atomic mass 15.9994 g·mol−1
Hydrogen: Atomic mass 1.00794g·mol−1
So, the compound you have requires the following amounts of each:
Chromium: 1
Sulfur: (1*3) = 3
Oxygen: (4*3)+(1*10) = 22
Hydrogen: (2*10) = 20
To calculate the mass of one mol of the compound, we must combine the mass of each component (at one mol of the compound) using the numbers above
Cr: 1*51.9961 grams/mol = 51.9961 grams
Sulfur: 3*32.065 grams/mol = 96.195 grams
Oxygen: 22*15.9994 grams/mol = 351.9868 grams
Hydrogen: 20*1.00794 grams/mol = 20.1588 grams
so, 1 mol of the compound has a mass of the sum of all the components above: 520.3367 grams
for 3.52 mol, that would be 3.52*520.3367 = 1831.5851 grams
2007-01-21 07:35:37 · answer #1 · answered by Daremo 3 · 0⤊ 0⤋
that divided by the molar weight in grams
2007-01-21 07:09:34 · answer #2 · answered by Flaming Pope 4 · 0⤊ 0⤋