Find the width of the rectangle.
2007-01-21 06:52:14 · 4 answers · asked by CelticMoonGoddess 2 in Science & Mathematics ➔ Mathematics
(L = 5 +2w
(2L + 2w = 52
2(5 + 2w) + 2w = 52
10 + 4w + 2w = 52
6w = 52 - 10
6w = 42
w= 42 : 6
w = 7
L = 5 + 2w
L = 5 + 2(7)
L = 5 + 14
L = 19 in
Answer: The width of the rectangle is 19 in.
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2007-01-21 07:08:54 · answer #1 · answered by aeiou 7 · 0⤊ 0⤋
It's impossible because their is way too much perimeter for the length of the rectangle to be more than twice the width.
2007-01-21 07:01:52 · answer #2 · answered by sexiinseductive 1 · 0⤊ 2⤋
w: x
L: 2x+5
P=2(w+L)
52= 2(x+2x+5)
52=2(3x+5)
52=6x+10
42=6x
x=7
w=7in
L= 2*7+5= 19in
2007-01-21 06:58:08 · answer #3 · answered by 7 · 0⤊ 0⤋
let w represent the width. let 2w represent the lenght.
w+w+2w+2w=52
6w=52
__ __
6 6
w=8.6
l=17.3
2007-01-21 07:06:17 · answer #4 · answered by Anonymous · 0⤊ 1⤋