most polyhedrans
have no special name, and most of those that do are defined by
special features such as parallel edges or congruent faces, so they
would not apply to the kind of general situation you are asking
about. For example, if a prism has this number of faces, edges, and
vertices, and you stretch the bottom, you can change it first to a
frustum of a pyramid, and then to a nameless distorted prism, without
changing the fact that it fits your description!
But you can look for _a_ familiar polyhedron that fits, rather than a
name that applies to _every_ such polyhedron. To do that, you can
start by looking for properties of familiar polyhedra in terms of
their faces, vertices, and edges. For example, suppose you have a
prism whose base is an n-gon. There are n lateral faces and 2 top and
bottom faces; n vertices each on the top and bottom; and n edges each
on the top, bottom, and sides. So you have
F = n + 2
V = 2n
E = 3n
Do the same for several other kinds of shapes (pyramids, perhaps
regular polyhedra and some others), and see whether what you are given
fits any of those.
2007-01-21 06:51:25
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answer #1
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answered by Anonymous
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Don't know if it's got a special name but a cube with the corner cut off will satisfy the conditions.
2007-01-22 19:53:22
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answer #2
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answered by tringyokel 6
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