Three people to be selected from four women and five men. There must be one man and one woman selected .?

Question

In how many ways can the three people be chosen. Subsequently, one of the men and women marry each other. The rules state that a married couple must not both be selected. In how many ways can the three people be chosen now.

Answer 1

Number of sets of three =
sets with two women and one man +
sets with two men and one woman
= 4c2 * 5c1 + 4c1*5c2
= 6*5 + 4*10 = 70

Now if a married man and woman are in a group then there are 7 other people who could be in the group with them. So there are 7 groups that are against the rules. So now there are 70-7 = 63 allowable groups.

Answer 2

The rules state that a married couple must not both be selected

that i dont get , how many of the man are married , how many of the woman you need to give that info

without his info i would say 1 man and 1 woman is possible in 4*5 then you have the option of either 1 man or 1 woman

so 4*5*( 3 + 4 )/2