Consider a sphere of surface area A and volume V. The volume of some other sphere that has twice the surface area (i.e. 2.00 A) is..
are they saying that the second sphere's surface area is 2.00..or you have to multiply by 2.0
2007-01-21 04:49:04 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Physics
i take the cubed of ths first..is 8 correct?
2007-01-21 05:15:25 · update #1
Area = 4 * pi * r^2
Volume = 4 / 3 * pi * r^3
To double the Area you have to increase the
radius by sqrt(2).
If you increase the radius by sqrt(2) the Volume increases
by 2*sqrt(2).
2007-01-21 05:16:46 · answer #1 · answered by themountainviewguy 4 · 0⤊ 0⤋
They are saying that the second sphere has twice the surface area of the first. That is, the second sphere has 2.00 times the surface area of A.
2007-01-21 14:56:53 · answer #2 · answered by LJUDAD 2 · 0⤊ 0⤋
Area varies with the square while volume varies with the cube, no matter what the shape is. If something has twice the surface area of another its linear dimension (in the case of a circle, its radius) is the square root of 2 times the first, so the volume will be that number cubed.
2007-01-21 13:05:49 · answer #3 · answered by hznfrst 6 · 0⤊ 0⤋
ok here goes
Surface is 4 PI R^^2
To get the surface to double you have to increase the radius by SQRT(2)
Volume of the new sphere is 4/3 PI RPrime^^3
The new radius RPrime is sqrt(2) * R
so
Volume = 4/3 PI 2 ^^(3/2) R^^3
so the new volume is 2^^(3/2) = sqrt(8) the original
2007-01-21 13:08:06 · answer #4 · answered by walter_b_marvin 5 · 0⤊ 0⤋
multiply by 2
2007-01-22 19:56:07 · answer #5 · answered by ha t 1 · 0⤊ 0⤋
multiply by 2
2007-01-21 13:11:48 · answer #6 · answered by chitrakg 2 · 0⤊ 0⤋