how to solve: x squared +3x-10=0?

Answer 1

oh gosh i cant belive how people here complicate a simple solution!!??

it is:


x2+3x-10=0

( x -2 ) ( x+5 )=0

X1= 2

x2= -5

There you have it. Hope it helped. Have a wonderful day. :))

Answer 2

once you should finish the sq. x^2 - 3x - 10 = 0 x^2 - 3x = 10 x^2 - 3x + (-3/2)^2 = 10 + (-3/2)^2 x^2 - 3x + 9/4 = 10 + 9/4 (x - 3/2)(x - 3/2) = 40 9/4 (x - 3/2)^2 = 40 9/4 x - 3/2 = ± ?(40 9/4) x - 3/2 = ± 7/2 x = (3 ± 7) / 2 x = {-2, 5} that is a lot extra reachable to component it x^2 - 3x - 10 = 0 (x + 2)(x - 5) = 0 x = {-2, 5}

Answer 3

x^2 + 3x - 10 = 0

First: factor the equation > multiply the 1st & 3rd coefficient to get "-10." Find two numbers that give you "-10" when multiplied & "3" (2nd/middle coefficient) when added/subtracted. The numbers are: 5 and -2 >>>

Sec: rewrite the expression with the new middle coefficients...

x^2 + 5x - 2x - 10 = 0

*When you have 4 terms - group "like" terms & factor...

(x^2 + 5x) - (2x - 10) = 0
x(x + 5) - 2(x + 5) = 0
(x + 5)(x - 2) = 0

Third: solve the two x-variables > place both sets of parenthesis to equal "0" >>>

1. x + 5 = 0
x+ 5 - 5 = 0 - 5
x = - 5

2. x - 2= 0
x - 2 + 2 = 0 + 2
x = 2

Soltuions: - 5 and 2

Answer 4

=>
x=-5 or x=2

Answer 5

You meant x^2 + 3x - 10 = 0. Use ^ for power.

You can use Bhaskara's formula: the solutions of ax^2 + bx + c = 0 are x = (-b +/- sqrt(b^2 - 4ac)) / (2a), provided that b^2 - 4ac >= 0.

Substituting the respective values into the formula:

x = ( -3 +/- sqrt(9 + 40) ) / (2 * 1) = (-3 +/- 7) / 2

Solution 1: x = (-3 + 7)/2 = 2
Solution 2: x = (-3 - 7)/2 = -5

Answer 6

x= -5 or 2

Answer 7

you can put it into a binomial like...

x^2+3x-10=0 into (X+5)(x-2)=0 and then do..

X+5=0 take away 5 from both sides x=-5

and X-2=0 add 2 to both sides x=2

you could also use the quadratic formula if its not a perfect trinomial or use completing the square method to make a a perfect trinomial

i

Answer 8

x^2 + 3x - 10 = 0
(x + 5)(x - 2) = 0

Answer 9

x^2 + 3x - 10 = 0
(x + 5)(x - 2) = 0

x = -5 or x = 2 are the two solutions

Answer 10

(x-2)(x+5)
x=-2 or 5