Algebra help!!!!?

Question

Find an equation for the line passing through the point (-5, -3) and having x- intercept 2.

Write the entire answer in any line form

Answer 1

First: find the slope > place the point and x-intercept in the slope-intercept form which is, "y = mx + b" > ("m" represents the slope and "b" represents the y-intercept)...

- 3 = m(-5) + 2
- 3 = - 5m + 2

Sec: subtract 2 from both sides...

- 3 - 2 = - 5m + 2 - 2
- 5 = - 5m

*Isolate "m" on one side > divide both sides by "-5"

- 5/-5 = (-5m)/-5
1 = m
m = 1

Third: place the slope, y-intercept and point in the point-slope formula which is, "y - first y = m(x - first x)

y - (-3) = 1(x - (-5))
y + 3 = 1(x + 5)
y + 3 = 1(x) + 1(5)
y + 3 = x + 5

*Subtract "3" from both sides...

y + 3 - 3 = x + 5 - 3
y = x + 2

Answer 2

The first step is to find the slope of the line. You probably know how to do this; I'll remind you. It is rise over run, or the difference in y divided by the difference in x, or, (y.1-y.0)/(x.1-x.0). (note, those are subscripts, not multiplications).

Okay, you have two points. One is (-5, -3). The other is (2, 0) since the x-intercept is where it crosses the x axis when y=0.

Once you figure out the slope of the line, you can put it in the slope-intercept form, which is: y=mx+b, where m is the slope and b is the y-intercept.

Answer 3

Okay. You know a point and an intercept. Thus, you actually know two points on the line. You can get an equation from two points as follows.

Step One: Identify your points. Here these are (x1, y1) = (-5, -3) and (x2, y2) = (2, 0).

Step Two: Find the slope using the points.
(y1 - y2)/(x1 - x2) = (-3 - 0)/(-5 - 2) = -3/-7 = 3/7.

Now, use the slope-point form of the lines equation.

y - y1 = m (x - x1)
y - (-3) = 3/7 (x - (-5))
y + 3 = 3/7 (x + 5)
y + 3 = 3/7x + 15/7
y = 3/7x - 6/7

Had we chosen the point (2, 0) notice that our equation would be the same.

y - 0 = 3/7 (x - 2)
y = 3/7x - 6/7.

Answer 4

y = (3/7) * (x-2)

You can write it in the form 7 * y = 3 * x - 6.

This is obtained from the relation:

y/(x-2) = 3 /(5+2) = 3/7

You see that when x = - 5 , y = -3, and for x = 2 is y = 0 (x axis interception)

Answer 5

Y=mX+b where b is the y intercept point when X=0 (not 2)
-3=m(-5) +2, m = 1
Y=X+2

Answer 6

By definition the equation is:
y = mx + b
Where:
m = slope
b = y-intercept (Note: this is the y-intercept)
Get hold of an Analytic Geometry textbook so you will fully understand your question.
It will be then a matter of substitution.

Answer 7

(-5,-3)(2,0)

0-(-3) / 2-(-5)
3/7

y=mx+b

0=3/7(2) +b
0=6/7+b
b= -6/7

y=3/7x-6/7

Answer 8

Do you mean y int is 2?

Answer 9

Sorry I am of no help but I feel your pain!