Two forces with magnitudes 8 N and 11 N act on a large object. The angel between the forces is 30degrees.?

Question

Two forces with magnitudes 8 N and 11 N act on a large object. The angel between the forces is 30degrees.
a) Draw a diagram to represent the combined effect of the forces.
b) Calculate the magnitude of the resultant force.

Answer 1

do your own homework! how do expect someone to draw a diagram on here?

Answer 2

a) From a point, draw an arrow 8 units long (say, 8 cm) and, at an angle of 30 degrees, draw another one 11 units ling.
Then, at the end of the line of 8 unit, draw a line parallel to the other vector and of length 11.
At the end of the original 11 unit vector, draw a line parallel to the original 8, and of length 8.

The two new lines should meet and the four lines form a parallelogram of force. The diagonal, from the start point to the finish point is the resultant force (the vectorial addition of the two forces). Measure its length in the same units to find the answer.

b) the easiest way is to consider one line as a basic orientation (e.g., along the x axis). Let's begin with the line of 11 units and line it up with the x axis: its end point is (11, 0).

The second line (length 8) will also begin from the origin (just as we did above) and is offset by 30 degrees (we'll assume upwards). Then its end point is (8*Cos(30), 8*Sin(30)) = (6.93, 4).

The resultant is found by adding the two points:
(11, 0)+(6.93,4) = (17.93, 4)

Distance from origin?
SQRT(17.93^2 + 4^2) = SQRT(337.5) = 18.37 N

Angle of resultant?
Tan(x) = 4/17.93
x = 12.6˚

Answer 3

sum of the horizontaly forces = 36 cos 225 + 40 8 cos 315 = 36 ( -a million/2 sqrt2) + 40 8 (a million/2 sqrt2) = 6sqrt2 sum of the vertically forces = 36 sin 225 + 40 8 sin 315 = 36 ( -a million/2 sqrt2) + 40 8 (-a million/2 sqrt2) = -40 two sqrt2 the magnitude of their equilibrant = sqrt{ (6sqrt2)^2 + (-40 two sqrt2)^2 } = sqrt( 72 + 3528) = sqrt3600 = 60 N the path : tan d = (sum of the vertically forces) / (sum of the horizontaly forces) tan d = (-40 two sqrt2) / (6sqrt2) tan d = -7 d = arc tan (-7)

Answer 4

whut angel
30degrees
maybe gabriel