2007-01-21 02:31:10 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This can only be proved if A+B+C=180 ,i.e., A,B,C are the angles of a triangle.
2007-01-23 05:32:04 · answer #1 · answered by HIMANSHU A 1 · 0⤊ 0⤋
If the decimal points mean multiplication, then the statement is not true. All you need to do is use the identity:
cot (x/2) = sinx/(1-cosx).
Then assign arbitrary values to A, B, and C and you will find that your identity does not work. If you use A= 60 degrees, B= 40 degrees and C = 20 degrees, you will get 10.15 = 26.98.
This should convince you that your expression is not an identity.
2007-01-21 03:09:21 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋
hey its very easy.......
(cotA/2+ cotB/2 +cotC/2)*0=(cotA/2. cot B/2 .cotC/2)*0
0=0
hence proved...............
2007-01-21 03:57:41 · answer #3 · answered by Anonymous · 0⤊ 1⤋
Write left hand side statement one side and leave 1 1/2 page then write Right hand side statement and then apply formula from L.H.S start writing down words and in same manner from R.H.S. and start writing up words.
I want you to tell the secret you can write ant thing in between when don't find formula's could be applied anymore.
Happy??
L.H.S. = R.H.S.
2007-01-21 02:40:29 · answer #4 · answered by pankaj s 3 · 0⤊ 1⤋
There is a missing assumption, such as A+B+C= pi or 2 pi or something!
2007-01-21 02:47:35 · answer #5 · answered by gianlino 7 · 0⤊ 0⤋
is it in a triangle?..something is missing.
2007-01-23 17:03:48 · answer #6 · answered by grandpa 4 · 0⤊ 0⤋