Hey, what is the difference between AB and AB with an arrow over it.
I'm guessing one is a vector the other is a scalar?
Why does |AB[arrow]| = |AB|
Thanks
2007-01-20 21:59:41 · 7 answers · asked by Philip J 2 in Science & Mathematics ➔ Mathematics
Yes Philip, you're right. AB without the arrow refers to the scalar, which then means the magnitude. Whereas AB with the arrow on top refers to the vector and thus the direction needs to be included.
eg. AB(->) = 3i+4j,
AB = square root of (3²+4²)=5
hmm... lAB(->)l=lABl cause they refer to the same thing. Just as I mentioned above, AB with the arrow refers to the vector and the absolute bars refers to the magnitude of the vector, hence they are equivalent mathematical terms.
2007-01-20 22:13:13 · answer #1 · answered by tabletennisrulez 2 · 0⤊ 1⤋
AB with an arrow over it is a vector and a vector has magnitude and direction.
AB without an arrow is a scalar quantity ie has magnitude only.
In 2 dimensions a vector AB may be (3,4).
In text books this would be shown with the 3 above the 4.
This means 3 parallel to x axis and then 4 upwards.
Scalar value of vector AB is then given by the square root of (3² + 4²) = 5
Note that scalar value has magnitude but no direction.
2007-01-20 23:38:04 · answer #2 · answered by Como 7 · 0⤊ 1⤋
AB with an arrow is a vector. Simply AB can be the distance between A & B.
|x| means the magnitude of that thing.
2007-01-20 22:59:16 · answer #3 · answered by nayanmange 4 · 0⤊ 1⤋
u know a vector quantity has both direction and magnitude but scalar has just magnitude
hence ab(arrow) is vector and hence have both whereas AB have magnitude and u r taking mod of both means calculating magnitud which has to be equal
2007-01-20 22:10:39 · answer #4 · answered by n nitant 3 · 0⤊ 0⤋
IABI[arrow] isnt equal to IABI its equal to IABI times n (cap) .. a unit vector in direction of AB (arrow)
2007-01-20 22:10:51 · answer #5 · answered by Anonymous · 0⤊ 1⤋
remember a vector can only be in a certain direction but a scalar quantity can be in ANY direction.
2007-01-20 22:13:14 · answer #6 · answered by jsd 2 · 0⤊ 1⤋
initiate with by using drawing the 10N vector first with the ultimate perspective, than the 6N vector follows by using the 5N. draw the consequent tension from the commencing up factor of 10N hook up with the top of 5N. degree the dimensions of the consequent tension and perspective.
2016-10-31 21:48:38 · answer #7 · answered by ? 4 · 0⤊ 0⤋