g(x+2)=(x+2)square-10x-3?

Answer 1

*You wrote it incorrect. It should be: solve the function when "x" is "x+2." The function is g(x) = x^2 -10x - 3

First: the problem gives you the value for the x-variable > replace "x+2" with the x-variables in the function...

g(x+2) = (x+2)^2 -10(x+2) - 3

g(x+2) = (x+2)(x+2) -10(x+2) - 3

g(x+2) = (x)(x) + (x)(2) + (2)(x) + (2)(2) -10(x+2) - 3

g(x+2) = x^2 + 2x + 2x + 4 -10(x+2) - 3

g(x+2) = x^2 + 2x + 2x + 4 -10(x) - 10(2) - 3

g(x+2) = x^2 + 2x + 2x + 4 -10x - 20 - 3

g(x+2) = x^2 + 2x + 2x - 10x + 4 - 20 - 3

g(x+2) = x^2 - 6x -19

Answer 2

g(x + 2) = (x + 2)^2 - 10x - 3

g(x + 2) = (x + 2)^2 - 10(x + 2) - 3 + 20
g(x + 2) = (x + 2)^2 - 10(x + 2) + 17

Therefore,

g(x) = x^2 - 10x + 17

Answer 3

g=17