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At 40°C, the value of Kw is 2.92 10-14. Furthermore, If the hydroxide ion concentration in a solution is 0.44 M, what is the pH at 40°C?

2007-01-20 16:18:54 · 5 answers · asked by Student_007 1 in Science & Mathematics Chemistry

5 answers

The self dissociation of water is

H2O <=> H+ +OH-

with Kw=[H+][OH-].

Kw changes with temperature and therefore the pH of pure water is different at different temperatures.

For pure water, according to the reaction above, [H+]=[OH-] thus

Kw=[H+]^2 => [H+]=Kw^(1/2) =>
pH= -log[Kw^(1/2)]= -(1/2)*log(Kw)
so pH= -0.5*log(2.92*10^-14) = 6.77.

For the second part,

Kw=[H+][OH-] =>
-log(Kw)=pH + (-log[OH-]) =>
pH= log(0.44) -log(2.92*10^-14) =13.18

2007-01-21 06:35:06 · answer #1 · answered by bellerophon 6 · 0 0

NONONO

The first answerer is correct, the pH of water does not change with temperature. However, the pH of water is 7 NOT 0!!!!!!

2007-01-20 17:49:54 · answer #2 · answered by podnaes 2 · 0 1

If the water is pure wouldn't the pH be 0?

2007-01-20 16:27:16 · answer #3 · answered by Floyd B 5 · 0 2

For water, the pH is always 0.

2007-01-20 16:27:30 · answer #4 · answered by Rodney I 2 · 0 2

pH shouldn't change no matter the temperature. I think. -_-;

2007-01-20 16:22:50 · answer #5 · answered by kawaiisuzakuwarrior 4 · 0 1

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