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Please explain:

An arrow is launched upward with an initial speed of 20 m/sec, how high (above the point of release) will the arrow travel?

2007-01-20 16:03:05 · 3 answers · asked by GSU 1 in Science & Mathematics Physics

3 answers

you need to provide thewe unknowns:
1. mass of arrow
2. drag of arrow
3. weight of arrow
4. sg of the atmosphere
5. moisture of the atmosphere
these will allow a much more accurate answer.

2007-01-20 16:26:57 · answer #1 · answered by dulcrayon 6 · 0 0

Conservation of energy:
1/2*mv^2 = mgh
dividing by mass, we get:
1/2*v^2 = gh

v = 20 m/s; g = 9.8 m/s^2

h = 1/2*(20 m/s)^2/(9.8 m/s^2)
h = 20.41 m

2007-01-21 00:50:24 · answer #2 · answered by thubanconsulting 3 · 0 0

20.38m

2007-01-21 00:15:09 · answer #3 · answered by Max T 2 · 0 0

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