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I have been working on this problem for two hours and I can not get it.

it is:::::::::

7x^5 y^5-21x^4+14x^3y^3
_____________________
7x^3y^3
I know his looks confusing and I am not sure how to better explain it. But all of the ^ means exponents of x or y please help me thanks.

2007-01-20 15:59:37 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

X^2Y^2 - 3x/(y^3) + 2 is what I have.

First take 7 out of numerator and denominator. You get:
7(x^5y^5 - 3x^4 + 2x^3y^3)
---------------------------------
7(x^3y^3)

7 cancells out

then take X^3 out
x^3(X^2Y^5 - 3x + 2Y^3)
-------------------------------
X^3(Y^3)

X^3 cancells out

Break them up....
(X^2Y^5)/Y^3 - 3x/(y^3) + (2y^3)/(y^3)

simplify.... you get:
x^2y^2 - 3x/(y^3) + 2

2007-01-20 16:21:45 · answer #1 · answered by tkquestion 7 · 0 0

divide the coefficients of the top x terms by the coefficients of the bottom x term and do the same with the y terms. After each division of coefficients subtract the exponent of the bottom term from the exponent of the top term. Work it left to right like so:

7x^5 y^5 - 21x^4 + 14x^3 3y^3
--------------------------------------
7x^3 y^3

7/7 = 1 x^5 - x^3 = x^2
y^5 - y^3 = y^2
-21/7 = -3 x^4 - x^3 = -3x
14/7 = 2 x^3 - x^3 = x^0 = 1 * 2 = 2
y^3 - y^3 = y^0 = 1

x^2 y^2 - 3x + 2(1) combine like terms

-3x^2 y^2 + 2

2007-01-21 00:38:23 · answer #2 · answered by ikeman32 6 · 0 0

you have to look at it as 3 terms:
7x^5y^5 - 21x^4 + 14x^3y^3
_______ _____ _______
7x^3y^3 7x^3y^3 7x^3y^3

now simplify:

x^2y^2 - 3x + 2
___
y^3

-OR-
x^2y^2 -3xy^-3 + 2

either way you write the answer is correct...it is just a matter of how comfortable you are with negative exponents.

Good Luck!

2007-01-21 00:18:56 · answer #3 · answered by Katie C 1 · 0 0

I got x^2y^5 - 3x + 2y^3
--------------------------
y^3

or another answer is
x^2y^2 - 3xy^(-3) + 2

They're both the same, just that i simplified the first one to get the second.

2007-01-21 00:13:20 · answer #4 · answered by stoopidbones 2 · 0 0

x^2y^2-3x+2

2007-01-21 00:06:17 · answer #5 · answered by Anonymous · 0 0

umm, i got x^2y^2-3x +2

2007-01-21 00:12:56 · answer #6 · answered by Anonymous · 0 0

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