I am struggling with this math problem.
x^2-2x-35
over
x+5
^2 means to the second power.
Thanks for the help.
2007-01-20 15:13:50 · 7 answers · asked by richardsonlover12 1 in Science & Mathematics ➔ Mathematics
Please use parenthesis > (x^2 - 2x - 35)/(x + 5)
First: factor the numerator > multiply the 1st & 3rd coefficient to get "-35". find two numbers that give you "-35" when multiplied &
"-2" (2nd/middle coefficient) when added/subtracted. The numbers are: -7 and 5
Sec: rewrite the expression with the new middle coefficients...
(x^2 - 7x + 5x - 35)/(x + 5)
*Combine "like" terms...
(x^2 - 7x) + (5x - 35)/(x + 5)
[x(x - 7) + 5(x - 7)]/(x + 5)
[(x - 7)(x + 5)]/x+5
Third: cancel "like" terms...
x - 7
2007-01-20 15:38:57 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
factor the numerator out so it becomes (x+5) * (x-7), which (when you multiply it back together, you get x^2-2x-35)
then you can cancel out the (x+5) in the numerator and denominator and you'll end up with x-7
i hope that makes sense.
2007-01-20 23:19:55 · answer #2 · answered by The Candyman 2 · 0⤊ 0⤋
(x^2-2x-35)/(x+5)
= (x-7)(x+5)/(x+5)
= x-7
2007-01-20 23:18:00 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
factor the numerator
(x+5)(x-7)
----------
x+5
(x+5) cancel out we left with (x-7)
2007-01-20 23:17:29 · answer #4 · answered by 7 · 0⤊ 0⤋
(x^2 - 2x - 35)/(x + 5) =
(x - 7)(x + 5)/(x + 5) =
x - 7
The other method is
. . . . x . . - 7
x + 5)x^2 - 2x - 35
. . . . x^2 + 5x
. . . . . . . - 7x - 35
. . . . . . . - 7x - 35
2007-01-20 23:34:38 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋
(x-7)(x+5)
________
x+5
2007-01-20 23:35:46 · answer #6 · answered by Helper X 2 · 0⤊ 0⤋
-3x-7
2007-01-20 23:18:09 · answer #7 · answered by melinda_trvn 2 · 0⤊ 2⤋