how do I do this?

Question

I am having some difficulties figureing out these problems and the textbook is not explaining it to well. I would ask my teacher but it is due on monday. Thank you in advance for any help.

find each of the following products:
a(a+5)(a-5)

and the other problem is
for each od the folwoing problems, let x represent the number then write an expression for the product.

The square of 5 more than a number.

Thanks again

Answer 1

1. Find the products for a(a + 5)(a - 5)

First: multiply the outer term > "a" with the terms in the 1st set of parenthesis...

a(a) + a(5)
a^2 + 5a

Sec: multiply the previous result with the 2nd set of parenthesis > use the foiling method...

(a^2 + 5a)(a - 5)

(a^2)(a) + (a^2)(-5) + (5a)(a) - (5a)(5)
a^3 - 5a^2 + 5a^2 - 25a
a^3 - 25a

2. Let "x" represent a number then write an expression for the product. The square of 5 more than a number.

*The last part is not typed correctly. Do you mean (5 more than a number) squared Or, five more than a (number)squared?

It could be:

a) (5 + x)^2

b) 5 + x^2

Answer 2

find each of the following products:
a(a+5)(a-5)
(a^2 + 5a) (a-5)
a^3 - 5a^2 +5 a^2 -25a
a^3 - 25a

and the other problem is
for each od the folwoing problems, let x represent the number then write an expression for the product.

The square of 5 more than a number.
(x+5)^2
(x+5)(x+5)
x^2 + 5x + 5x + 25
x^2 +10x + 25

Answer 3

why am i answering all these math questions? CUZ I'M A HOPELESS GEEK!!! lol

ok the first one is easy. distribute the a through (a+5just use FOIL to multiply them together separately. (FOIL = first, inner, outer, last. its a way to remember how to multiply a polynomial. i only explain because i don't know if you're familiar with FOIL)

1) first use FOIL on (a+5)(a-5)
multiply the first two terms (a*a)
then multiply the outer two terms (a*-5)
then the inner two (5*a)
then the last two (5*-5)
then add it all up (a^2 -5a + 5a -25) which equals a^2 -25

then just distribute the a through the (a^2 - 25) and it becomes a^3 -25a

2) x is the number
you want the square of 5 more than the number
that means the square of (x+5)
which is (x+5)^2
which expands (by FOIL) into x^2 + 5x +5x + 25
OR x^2 + 10x + 25

hope that helps :)

Answer 4

First question:
a(a+5)(a-5) =
a(a^2 + 5a - 5a -25) =
a(a^2 - 25) =
a^3 - 25a

Second question:
You are looking for the square of 5 more than the number x.
5 more than x can be written as (x+5).
The square of this number is (x+5)^2.
Thus, the answer is: (x+5)^2.
If you want to expand this:
(x+5)^2=
(x+5)(x+5)=
x^2 + 5x + 5x + 25 =
x^2 + 10x + 25

Answer 5

a^3 - 25a
This is a difference of two squares. Any time you have a product of two binomials, with the same thing in each place, and a plus in one and a minus in the other, this is called a product of conjugates and it multiplies out to a difference of two squares.
If you FOIL out the (a+5)(a-5) you'll see that the middle terms cancel out and you wind up with just a^2 - (5^2) = a^2 - 25. Then multiply in the a and you get a^3 - 25a
For the next one,
(n+5)^2
call the number n or x or whatever letter you want. Add 5, that's (n+5) Finally, square it, that's (n*5)^2
It's important to understand this. It's not hard once you understand. There are some good online explanations of these, see
http://www.purplemath.com and
http://www.sosmath.com
for starters

Answer 6

a million:bypass to the ask bar 2:put on your question 3:it is going to take to were you may wright your question. 4:hit post 5:it provides you with recommendations in what your questions topic is about 6:hit post lower back 7:your executed! 8:in case you want an party use yours :) stupid!

Answer 7

1, a(a^2-25)
=a^3-25a

2, X+5^2

Answer 8

a*3 -25a; (x+5)*2. Neither of these is difficult, so be sure you understand the results.

Answer 9

Well that sa good question but to tell u the truth in my school we are working on th esame thing and i really didnt understand it but i did understand in eo fthem the "The sqaure of 5 more than a number"..... its 25+m

welll abviusly u can put anything for the variable

Answer 10

i believe the answer to the first question is 6a^2+25a