a³ - 16ab²
Factor out the a:
a(a² - 16b²)
The second factor is what is called a "difference of squares".
Whenever you have x² - y², it ALWAYS factors as (x + y)(x - y), which you can verify using FOIL). In this case, x = a and y = 4b, so:
a(a + 4b)(a - 4b)
2007-01-20 15:16:44
·
answer #1
·
answered by Jim Burnell 6
·
0⤊
0⤋
First, you want to take out any common terms. a is a common term for both, so first factor out an a, giving you
a (a^2 - 16b^2)
Now factor (a^2 - 16b^2)
Notice that you only have two terms; therefore you know that you have to have two factors of -16 that cancel each other out, which would be 4 and -4. Now factor:
(a + 4b) (a - 4b) = a^2 -4ab +4ab - 16b^2
Notice that the 4ab and -4ab cancel out like I said before, giving you a^2 - 16b^2. Now multiply by a giving you
a(a^2 - 16b^2) = a^3 - 16ab^2, so it checks.
a(a + 4b) (a - 4b) is your answer.
2007-01-20 23:27:21
·
answer #2
·
answered by j 4
·
0⤊
0⤋
Factor out an a, giving
a(a^2-16b^2)
This factors into
a(a + 4b)(a - 4b)
2007-01-20 23:24:52
·
answer #3
·
answered by Helmut 7
·
0⤊
0⤋
first divide it with an a
a(a^2-16b^2)
then factorise
a(a-4b)(a+4b)
2007-01-20 23:16:43
·
answer #4
·
answered by Helper X 2
·
0⤊
0⤋
a³-16ab² =
a(a² - 4b²) = a(a-4b)(a+4b)
><
2007-01-21 11:12:03
·
answer #5
·
answered by aeiou 7
·
0⤊
0⤋