hey so basically the title says it all, but I checked my sprint sanyo scp 3100 cellphone and it said i have a missed call, and the name was "UNKNOWN". I was wondering if it's possible to check the # of the caller, so I could see if I knew the person. Does anyone know how?
~Thanks~!
2007-01-20 15:09:43 · 6 answers · asked by Anonymous in Consumer Electronics ➔ Cell Phones & Plans
used to work for Sprint for less than 2 yrs.
no guarantee in retrieving unknown #s
for legal or police purposes, the local law enforcement agency is the only one who can contact Sprint for a call trace (but there's still no guarantee that the # will be retrieved).
2007-01-23 00:57:16 · answer #1 · answered by Nina Flores 2 · 0⤊ 0⤋
if the number is "unknown" it was blocked for a reason so there is no way to unblock it or find out the number for me it was "withheld" I dont know if they have it for cell phones because I know they have it for land phones but you can call your phone company up and ask for a privacy call manager. Then the caller has to unblock their number in order to reach you. Hope it works
2007-01-20 23:22:08 · answer #2 · answered by foss_jnll 2 · 1⤊ 0⤋
With most MOBILE CARRIERS like T*MOBILE, SPRINT/NEXTEL and others, SADLY there isn't a way to obtain the #.
W/T*MOBILE: When I get a CALL W/BLOCKED/UNKNOWN #, I try CALLIN' 611, 411, they CAN'T TRACE # or if, VOICEMAIL, MSG CENTER CAN NOT get #.
2007-01-20 23:55:17 · answer #3 · answered by NOKIA 6103 By T*MOBILE 3 · 0⤊ 0⤋
sometimes your cell carrier has a website you can log on and you MAY be able to see your incoming and outgoing call log on there. i know it would work if you were a cingular customer, i guess it depends on who your carrier is. good luck
2007-01-21 00:28:39 · answer #4 · answered by swan5250 2 · 0⤊ 0⤋
It means they dialed *67 before they called and there is no way to figure out who it was.
2007-01-20 23:22:06 · answer #5 · answered by Alex F 2 · 1⤊ 0⤋
I don't think so. If it's blocked, there really isn't any way to get it.
2007-01-20 23:14:09 · answer #6 · answered by Anonymous · 0⤊ 0⤋