Add 3 from both sides:
2x=7
Divide 2 from both sides:
x=7/2
Check:
2(7/2)-3=4
7-3=4
4=4
2007-01-20 14:41:15
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answer #1
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answered by Anonymous
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6-4(x-3)=2x-4(2x-3) distribute the -4, and the -4 6 - 4x + 12 = 2x - 8x + 12 subtract 12 from both sides 6 - 4x = 2x - 8x combine terms 6 - 4x = -6x add 4x to both sides 6 = -2x divide by the variable's coefficient (which is -2) -3 = x Hope this makes things clearer!
2016-05-24 03:03:14
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answer #2
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answered by Anonymous
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This is a very straightforward algebra problem.
If you are having trouble with this you probably need to review the common methods for solving simple equations.
They generally consist of applying the same multiplication, addition, division, or subtraction to both sides of the equation. By doing the same thing to both sides, the equation is still the same, still equal, although it is expressed differently then and can show the value of the chosen variable.
add 3 to each side
2x -3 +3 = 4 + 3
2x = 7
divide each side by 2
2x/2=7/2
x=7/2
good luck
keep at it
2007-01-20 14:46:48
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answer #3
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answered by enginerd 6
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2x - 3 = 4
you want to find x, get all other numbers on the right hand side of the equation,
2x - 3 = 4
2x = 4 + 3
(-3 becomes +3 when its taken on the other side of the equation)
2x = 7
x = 7/2
(2 multiplied by 'x' will become denominator when taken on the other side of the equation)
x = 3.5
2007-01-20 14:45:16
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answer #4
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answered by Sherlock H 2
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2x -3 =4
u want to get the "X" by itself so u want to get rid of that -3
add 3 to both sides and it will be
2x=7
now divide :)
x = 7/2
2007-01-20 14:40:39
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answer #5
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answered by Amanda 5
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x= 7/2
2007-01-20 14:41:28
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answer #6
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answered by Gen 4
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2x-3=4
+3 +3
2x=7/2
x=3.5
THE ANSWER IS 3.5. X IS 3.5
2007-01-20 15:08:18
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answer #7
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answered by BullShit Man 2
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2x-3=4
2x=7
x=3.5
2007-01-20 14:41:55
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answer #8
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answered by Jen G 3
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2x-3=4
add 3 to the four
2x=7
divide by 2
x=3.5
first poster is pretty much dumb
2007-01-20 14:42:35
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answer #9
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answered by Anonymous
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2x - 3 = 4
+3 +3
___________
2x = 7
__ __
x = 3.5
2007-01-20 14:43:03
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answer #10
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answered by hi. 3
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