Evaluate b^2-2bc+c^2?

Question

b = 3

c = -2

I keep getting 29, but I think that's wrong I also get 17. Is it 17 or 29?

Serious replies!

Answer 1

*Its important to use parenthesis.

first: the problem gives you the values for the variables

sec: place the values with the corresponding variables in the expression

(3)^2 - 2(3)(-2) + (-2)^2

Third: solve the expression according to order of operations >
PEMDAS > > > ( ), exponents, multiplication, division, addition & subtraction...

(3)(3) - 2(3)(-2) + (-2)(-2)

9 - 2(3)(-2) + 4

9 - 2(-6) + 4

9 + 12 + 4

21 + 4

= 25

Answer 2

remember the order of operations Please Excuse My Dear Aunt Sally

first lets plug in the variables
3^2 - (2 * 3 * -2) + -2^2 do the parenthesis first

I like to do the multiplication from left to right because its simpler

-2 * 3 = 6 * -2 = 12
you now have 3^2 + 12 + -2^2

now do exponents
3^2 = 3 * 3 = 9
-2^2 = -2 * -2 = 4

you now have 9 + 12 + 4 I think you can take it from here.

Answer 3

That's
(b-c)^2
Substituting
(3-(-2))^2 =
(3+2)^ = 5^2 = 25

Answer 4

question is attracting many diverse solutions because some imagine that b2 = 2 x b and some imagine b2 = b² . i go for b² !!!:--- b² - 2bc + c² (- 4)² - 2 (- 4) (- 2) + (- 2)² 16 - 16 + 4 4

Answer 5

b²-2bc+c² =
3² - 2.3.-2 + -2² = 9 + 12 - 4 = 17
The answer is 17.
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Answer 6

b^2-2bc+c^2
=(b-c)^2 = (3-(-2))^2 = (3+2)^2 = 5^2 = 25
Sorry, but both your answers were wrong.

Answer 7

3^2-2(3)(-2)+(-2)^2
9+12+4
25

Answer 8

(3)^2-2(3*-2)+(-2)^2
9+12+4
21+4
25

Answer 9

b^2-2bc+c^2
factor it to get
(b-c)^2
b = 3
c = -2
(3- (-2))^2
(5)^2
25
I guess both your answers were wrong.