x^3-2x^2-24x?

Question

x^3-2x^2-24x

Answer 1

x(x² - 2x - 24)
x(x - 6)(x + 4)

Answer 2

I'm assuming you want us to factor it.

Step 1) Always factor out x's

x^3 - 2x^2 - 24x = x(x^2 - 2x - 24)

Step 2) Find two numbers that add up to b (in this case, -2) and multiply to give c (in this case, -24). If the coefficient of x^2 wasn't 1, this step would be slightly different.

4+(-6)=-2, 4*-6=-24

Step 3) Write down the factored form (x plus first number times x plus second number)

(x+4)(x-6)

Remember that we factored out an x earlier, so the entire thing is x(x+4)(x-6)

Answer 3

I assume you have to factor, correct? x^3 - 2x^2 - 24x

First: find the least common factor which is "x"

x(x^2 - 2x - 24)

Sec: factor the expression in parenthesis > multiply the 1st & 3rd coefficient to get "- 24". Find two numbers that give you
"-24" when multiplied and the 2nd/middle coefficient (-2) when added/subtracted. The numbers are: "-6 and 4"

*Rewrite the expression with the new middle coefficients...

(x^2 - 6x + 4x - 24)

Third: when you have 4 terms - group "like" terms...

(x^2 - 6x) + (4x - 24)
x(x - 6) + 4(x - 6)
(x - 6)(x+4)

*Also, please remember to combine the x-variable that was factored earlier.

x(x - 6)(x + 4)

P.S. You don't find the values for the x-variables because the original expression is not set to equal zero.

Answer 4

x^3 - 2x^2 - 24x = x(x^2 - 2x - 24) = x(x - 6)(x + 4)

Answer 5

x³-2x²-24x =
x(x² - 2x - 24) = 0
delta = (-2)² - 4.1.-24
delta = 4 + 96
delta = 100

x = (2 +/- sqrt 100) : 2
x' = (2 + 10) : 2 = 6
x" = (2 - 10) : 2 = -4
Solution: {x elements of R | x' = 6, x" = -4 and x"' = 0}
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Answer 6

x^3 - 2x^2 - 24x
= x(x - 6)(x + 4)

Answer 7

f(x) = x(x^2 - 2x - 24) = x(x + 4)(x - 6) roots - 4, 0, 6

Answer 8

Factor out an x:
x(x^2-2x-24)
x(x+4)(x-6)

Set it to zero:
x(x+4)(x-6)=0
x=0
x+4=0
x-6=0
x=0,-4, and 6

Answer 9

x=-4
x=6
x=0

Answer 10

x = 12 i think, (you factor it out two times)