1. Write in simplified radical form: 3sqrt3/4. is the answer: 1/4
2. Write in simplified radical form: 4sqrt3x5/81y3.
3. Solve: z 3 = -343 is the answer: {7}
4. Find all real solutions: 4 (x-5) 9 = 0 is the answer: {0}
5. Find all real solutions: x 2 + 49 = 0 is the answer: {7}
6. Find all real solutions: (q-4) 2 - 2= 0 is the answer: {4-sqrt2}
7. 3sqrtz-2=4 is the answer: 0
8. Solve: z 1/2 =4 is the answer: {2}
9. Solve: 3x 2 + 5=11 is the answer: {-sqrt2, sqrt2} ?
10. The diagonal of a square measures 10 inches. What is the lenght pf the sides? is it? 5 iches?
2007-01-20 12:45:37 · 9 answers · asked by hans d 1 in Science & Mathematics ➔ Mathematics
1. please read your book to write the problem correctly.
2. please read your book to write the problem correctly.
3. Solve: z^3= -343 and the answer is not 7
First: eliminate the exponent - find the cube root of both sides (you can only find the cube root of a negative number)...
V`(z^3) = V`(-343)
z = V`(-7)(-7)(-7)
z = - 7
4. do you mean: 4(x-5)^9 = 0? the answer is not "0"
First: divide both sides by "4"
[4(x-5)^9]/4 = [0]/4
(x-5)^9 = 0
Sec: eliminate the exponent - find the 9th root of both sides...
V`(x-5)^9 = V`0
x-5 = 0
Third: solve for "x" - isolate "x" by adding 5 to both sides...
x - 5 + 5 = 0 - 5
x = 5
5. Find all solutions: x^2 + 49 = 0 > the answer is not 7
First: isolate "x^2" on one side > subtract "49" from both sides...
x^2 + 49 - 49 = 0 - 49
x^2 = - 49
Sec: eliminate the exponent > find the square root of both sides...
V`(x^2) = V`(- 49)
x = V`(- 49)
Third: rule - you can't find the square root of a negative number. you have to make "49" positive by pulling out an imaginary "i" which is the negative sign.
x = i V`(49) and now, find the square root of "49"
x = 7i
6. do you mean: (q - 4)^2 - 2 = 0?
First: add "2" to both sides...
(q - 4)^2 - 2 + 2 = 0 + 2
(q - 4)^2 = 2
Sec: find the square root of both sides...
V`(q - 4)^2 = +/- V`2
q - 4 = +/- V`2
Third: isolate "q" on one side - add "4" to both sides...
q - 4 + 4 = 4 +/- V`2
q = 4 + V`2 and 4 - V`2
7. please read your book to write the problem correctly.
8. do you mean: z^(1/2) = 4? the answer isn't "2"
First: eliminate the exponent - raise both sides by the reciprocal of "1/2" which is "2" (flip the fraction)...
(z^1/2)^2 = 4^2
z = 16
9. your answer is correct - good job!
10. your answer is correct - good job! If the diagonal is 10, the length of the sides are "1/2" of 10 which is 5 in.
2007-01-20 15:01:00 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
3sqrt(3/4) = 3sqrt(1/4)*sqrt(3) = (3)(1/2)sqrt(3) = (3/2)sqrt(3)
4sqrt3x5/81y3=4sqrt(15/y)sqrt(1/81y^2)= (4/9y) sqrt (15/y)
z^3 = -343 --> z = -7
If this is 4*9*(x-5) the answer is 5
X^2+49 has no real solutions. The answer is +/- i
(q-4)^2 = 2 --> q-4 =+/- sqrt(2) -> q = 4 +/- sqrt(2)
3sqrt(z) -2=4 --> 3sqrt(z) =6 --> sqrt(z) =2 --> z = 4 or if you meant 3sqrt(z-2)=4 --> sqrt(z-2)= 4/3 --> z-2=16/9 --> z=2+16/9
z 1/2 =4 Sorry, Don't understand this.
3x^2 +5=11 --> 3x^2=6 --> x^2=2 -. x=+/- sqrt(2) You got it!!
d=s*sqrt(2) so s = d/sqrt(2) =10/sqrt(2) = 5sqrt(2)
2007-01-20 13:20:47 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
1. No
2. ??
3. No, is this supposed to be z to the 3rd power? If z to the 3rd is negative, then z must be negative.
4. No
5. No -- if the x 2 means squared, you can't have a real solution
6.
7. No
8. Yes
9.
10. NO - use trigonometry a squared plus b squared = c squared
2007-01-20 12:52:40 · answer #3 · answered by someone's mom 3 · 0⤊ 1⤋
various the important matters lined in Algebra I contain fixing equations and inequalities in a unmarried variable, graphing utilizing 2 variables (x & y), factoring and fixing quadratic equations, fixing fractional equations, and difficulty fixing (note problems with numerous varieties). Many pre-Algebra classes contact on all of those, yet Algebra I covers them extra thoroughly. maximum of those skills are used lower back in Algebra II, yet are then equipped upon and accelerated to apply in new strategies.
2016-12-02 19:44:51 · answer #4 · answered by ? 4 · 0⤊ 0⤋
u want me to do your math you crazy kid?????
get a grip crazy dude......
But here anyways for you:
1. 2radical 3
2. 1
3. 4
4. 1/2 pi
5. None
6. Infinity
7.
man i give up
2007-01-20 12:49:42 · answer #5 · answered by magnet4trouble 4 · 0⤊ 1⤋
i thikn you got most of them right im in algrebra to its hard all numbers and stuff i think #3 is 7z
2007-01-20 12:49:55 · answer #6 · answered by Anonymous · 0⤊ 0⤋
were not doing ur homework 4 u
2007-01-20 12:48:23 · answer #7 · answered by ur name here 1 · 0⤊ 1⤋
Do your own homework!! Cheater!! i'm telling your teacher.
2007-01-20 12:48:17 · answer #8 · answered by jones 1 · 0⤊ 1⤋
don't know what a slide rule is for
2007-01-20 12:47:57 · answer #9 · answered by kurticus1024 7 · 0⤊ 2⤋