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2007-01-20 07:13:15 · 8 answers · asked by palakkadchikku 1 in Science & Mathematics Mathematics

8 answers

It think it has an expotenial curve.

2007-01-20 07:22:32 · answer #1 · answered by Brenmore 5 · 0 1

Square Number Patterns

2016-12-17 03:09:12 · answer #2 · answered by ? 4 · 0 0

An interesting pattern is that the square of any whole positive real number equals the square of the the number one less than it plus the number one less than it plus the number whose square is in question. For example, five squared is 25. Six squared is 25 plus five plus six. This has some utility when trying to determine quickly the square of a number one more than a number whose square you already know. This works in reverse as well - 20 squared is 400, so 19 squared = 400 minus 20 minus 19, or 361.

2007-01-20 07:20:18 · answer #3 · answered by byhisello99 5 · 2 0

0^2 = 0
1^2 = 1
2^2 = 4
3^2 = 9
4^2 = 16

The differences between the consecutive squares shown above are 1, 3, 5, and 7, though if you extrapolate, you'll see they're all the odd numbers. Add 9 to 16 to get 5^2, add 11 to 25 to get 6^2, etc.

2007-01-20 07:21:39 · answer #4 · answered by wheezer_april_4th_1966 7 · 0 0

The square of any number is ALWAYS one more than the product of the number immediately before and the number immediately after. eg 5 squared is 25, and 4 muliplied by 6 is 24....

2007-01-20 07:23:03 · answer #5 · answered by Anonymous · 2 0

The pattern in square numbers is
that you should look in a hundreds chart
and find 2.
Then see the number that is diagonal
from it. Thoose are square numbers.

2007-01-20 07:39:05 · answer #6 · answered by Candy thunder 2 · 0 0

1square =1
2 square = 4
3 square = 9
4 square = 16
5 square = 25

25 = 16+9
16= 9+7
9= 4+5
4= 2+1

notice the pattern ????....interesting....
im not sure but i think this has sumthing 2 do with the binomial theorem.....pls correct me if im wrong....

2007-01-20 07:26:32 · answer #7 · answered by me_moi 2 · 0 0

well, one pattern is that they are all square.

2007-01-20 07:15:53 · answer #8 · answered by Anonymous · 0 1

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