I generally understand my Trig problems, but there is one I'm confused on.
The directions: "Find the exact solution to the equation for the interval 0 less than/equal to x less than 2 pie.
The problem: 2cosx^2 = 1
This is what I have gotten the equation to: cosx = the square root of 1/2.
I have to match up the square root of 1/2 to radians (In Pie) but there isn't a square root of 1/2...
So my question is, how do I get rid of the square root sign completely?
2007-01-20 07:02:42 · 3 answers · asked by Skye R 2 in Science & Mathematics ➔ Mathematics
there isn't a square root of 1/2...
What do you mean? Of course there is and that's cos pi/4.
2007-01-20 07:11:47 · answer #1 · answered by gianlino 7 · 2⤊ 1⤋
Typically, cos x^2 means cos ( x^2 )
and cos^2 (x) means ( cos x ) ^2.
The way you've got the problem written, you're looking at matching cosine to 1/2, then finding the square root of that radian.
btw, your name reminds me of a good friend I knew in college in little brown-town texas...
2007-01-20 15:18:18 · answer #2 · answered by brothergoosetg 4 · 1⤊ 0⤋
Yes, there is a square root of (1/2). It is + and - .707. Now you do not have the square root sign anymore!
Don't get discouraged. Just trudge on and you'll get there.
2007-01-20 15:12:09 · answer #3 · answered by Aldo 5 · 0⤊ 1⤋