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How do you do it?

2007-01-20 06:10:52 · 4 answers · asked by jrrkidd 1 in Science & Mathematics Mathematics

4 answers

1/n + 3/(2n)= 5/8

Multiplying both sides by n (and supposing n <> 0):

1 + 3/2 = 5n/8

5/2 = 5n/8

1/2 = n/8

n = 8/2 = 4

2007-01-20 06:15:22 · answer #1 · answered by jcastro 6 · 0 0

Change 1/n to 2/2n and add.

2/2n + 3/2n = 5/8
(2+3)/2n = 5/8
5/2n = 5/8
2n = 8
n = 4

2007-01-20 14:15:50 · answer #2 · answered by ecolink 7 · 0 0

Please let us know if you tried the problem-what is your result?
I'm assuming your solving for the variable "n"

1/n + 3/2n = 5/8

First: eliminate the parenthesis > multiply the denominators by everything....

(2n)(8)(1/n) + (2n)(8)(3/2n) = (2n)(8)(5/8)

Sec: cross cancel "like" terms & combine the remaining terms...

(2)(8)(1) + (8)(3) = (2n)(5)

16 + 24 = 10n

40 = 10n

Third: solve for "n" by isolating it on one side > divide both sides by "10"

40/10 = 10n/10
40/10 = n

n = 40/10
n = 4

2007-01-20 14:17:37 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0 0

1/n + 3/2n= 5/8
LCF(n, 2n, 8) = 8n
8 + 12 = 5n
5n = 20
n = 20 : 5
n = 4
S = {4}
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2007-01-20 16:10:25 · answer #4 · answered by aeiou 7 · 0 0

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