A 33 1/3 rpm has a radius of 15 cm. What is the linear velocity of a point on the rim in cm/sec?

Answer 1

v = rω = 15 cm × (33 1/3 rev/min) × (2π rad/rev) × (1 min/60sec)

v = 50/3 π cm/s ≈ 52.36 cm/s

(What's a 33 1/3 rpm? ;c) Kidding....I'm 34, and I have a record player.)

Answer 2

"A 33 1/3 rpm [RECORD?] has a radius of 15 cm. What is the linear velocity of a point on the rim in cm/sec?"

perimeter = 2πr

100/3 rpm = (100/3)*60 rps = 6000/3 (2π15) cm/sec

Voila

Answer 3

The belt must travel 6 times the circumference of the pulley per second, or 22pi*6 cm/sec, or 22pi*6/100 m/sec. Since the rim of the pulley and the driving belt must move at the same speed (assuming that there is no slipping), the distance travelled by any point on the rim of the pulley will be equal to the linear distance travelled by a point on the belt, per unit time. The distance travelled by a point on the rim of the pulley will be equal to the circumference of the pulley (pi*diameter ot 2pi*radius) multiplied the number of rotations per second. Finally, since the answer requested was in meters/second rather than centimeters, you must divide by 100 to obtain an answer in the correct units.

Answer 4

The linear velocity, v= Wr where W(generally written as the Greek symbol omega) is the rotation rate and r is the radius.

therefore v = (99/3)x 15 cm min^-1 or 495 cm min^-1
or 8.25 cm sec^-1

Answer 5

diameter=30
circumference = 30xpie
30x3.14159x33.333=velocity in cm/min
devide by 60 to get in seconds=52.3597cm/sec

Answer 6

Okay......

Length around the rim of the record = 2*pi*R...or 30*pi

Speed of record = 60 sec./33.3333 = 1.8 sec for each revolution of the record.

Distance = 30pi cm
Time = 1.8 sec

Rate = distance/time

= 16.66667*PI cm/sec. or about 52.33 cm/sec.

Answer 7

is rpm revolution per minute?

Answer 8

change to sec

60s/ (100/3rel) = 1.8s

V=2*pi*r / T
V= 2*pi*15cm / 1.8s
V=52.35cm/s