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I am assuming you are asking if the density of the cosmos is constant (many astronomers use the term universe for what we laymen call galaxy).

And, it is an interesting question. Stars lose mass continuously because the process of fusion not only results in the creation of new elements (hydrogen fuses to become helium, and other elements fuse to become still others(up to iron, but that's another discussion)), but also the helium weighs a bit less than the hydrogen used up to make it (the difference is emitted as electomagnetic energy). But, it would not take very much new matter per million cubic kilometers to make up the difference. If there is a mechanism that does, indeed, create matter from energy (outside laboratories, which can be neglected) then the density of the cosmos may be constant.

Another point is that the cosmos is known to be expanding, so if the density of the cosmos is to remain constant then there has to be such a mechanism. Remember, the "Big Bang" Theory implies a point source for the pre-cosmos, and that point source either had to include all the matter in the cosmos (either as matter, energy, both, or some other form) at the outset, or there is in place a (currently unknown) mechanism to create matter and/or energy out of nothing since that time.

My guess (and it is a guess based on an acceptance of the Big Bang, because that's where all the scientific information leads at this point in time) is that the density of the cosmos is decreasing in terms of both energy and mass.

2007-01-20 06:36:04 · answer #1 · answered by David A 5 · 0 0

As rely could be switched over to capability E= MC^2, the mass can't be consistent. The sum of the two could be simply by concepts of conservatism. I don’t think of all individuals has a diverse answer as ninety 5% of the universe continues to be the unexplained darkish rely or darkish capability

2016-12-12 16:03:17 · answer #2 · answered by ? 4 · 0 0

N/A

How to measure total mass?

Its volume?

What is volume /seconds?

2007-01-20 05:36:21 · answer #3 · answered by _LEV_ 2 · 0 0

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