What is a_n if n=2, a_1=4 and a_n= a_n-1 + 1 ?

Question

Any time I use the _ it means instead of being raised it is lowered small number...so..
What is a_n if n=2, a_1=4 and a_n= a_n-1 + 1 ?
I don't know how to set up, or answer these types of questions.

Answer 1

a_n if n=2
a_1 = 4

a_n = a_(n-1) + 1 | substitute n with 2
a_2 = a_(2-1) + 1
a_2 = a_1 + 1 | subtitute a_1 with 4
a_2 = 4 + 1
a_2 = 5

Answer 2

a_n-a_n-1 =1 So the a_n are consecutive numbers
As a_1= 4 =1+3 a_2=5 =2+3 ......... a_n= n+3

Answer 3

Given:

n = 2

a[1] = 4
a[n] = a[n - 1] + 1

That means you want to solve for a[2].

We have a recursive sequence; a sequence dependent on the previous terms. Therefore, we just solve a[2] by its definition.

Since a[n] = a[n - 1] + 1, then
a[2] = a[2 - 1] + 1
a[2] = a[1] + 1

Plugging in a[1] = 4,

a[2] = 4 + 1 = 5

Answer 4

a_2 = a_1 + 1
a_2 = 4+1 =5