c^2= a^2+b^2
c^2=(6)^2+(8)^2
c^2=36+64
c^2=100
c=10 feet
this isnt +/- because a line seg must be measured in + feet only
2007-01-20 03:59:37
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answer #1
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answered by painfully yours 3
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It's odd that this is college algebra ... I recall learning this stuff in 9th grade. Unless college means something different someplace else.
For c^2 = a^2 + b^2, c is the hypotenuse. We're given the measurements of the other two sides (6 feet and 8 feet), so assigning a = 6 and b = 8, we have
c^2 = 6^2 + 8^2
c^2 = 36 + 64
c^2 = 100
Now, take the square root of both sides, to get
c = +/- 10
However, triangle measurements can never be negative, so discard the negative solution, and
c = 10
2007-01-20 03:59:18
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answer #2
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answered by Puggy 7
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In this problem, a=6 and b=8 and c is the length of the hypotenuse.
So substitute those values into the Pythagorean Theorem and you get 6^2 + 8^2 = c^2
So that's 36 + 64 = 100 = c^2
The square root of 100 is exactly 10, which is the length of the hypotenuse.
2007-01-20 04:01:05
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answer #3
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answered by Jay Sherman 1
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LOL! Wait 'till you run into 'the calculus'! This stuff is easy by comparison. You should be able to do this in your head. 6^2 is 36, 8^2 is 64. 36+64=100. And you don't even need a calculator to know that the square root of 100 is 10.
The other thing you could have done was recognize that you were given a 3-4-5 right triangle, doubled in size.
BTW, this is high school geometry, not college algebra.
2007-01-20 04:00:45
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answer #4
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answered by Anonymous
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c^2 = 6^2 + 8^2 = 100,
so c = 10.
2007-01-20 04:16:32
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answer #5
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answered by steiner1745 7
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10
You should know that a 3,4,5 triangle is a right triangle because
3^ +4^2 = 5^2 [9+16=25]So any multiples of this are also right triangles. that means triangles with sides of 6,8,10 and 9,12,15 and 12,16,20, etc are also right triangles.
5, 12, 13 is another rt triangle because 25 +144 = 169.
Try to remeber these combinations and so when they pop up ypu can immediately state the answer.
2007-01-20 04:04:21
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answer #6
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answered by ironduke8159 7
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c^2 = a^2 + b^2 = 6^2 and 8^2 = 36 + 64 = 100
c^2 = 100
c = square root of 100 = 10
2007-01-20 03:59:03
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answer #7
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answered by dietbarqs12345 3
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god damned algebra... I-hate-it. and im no longer speaking about computing stuf flike matrix operations, exponenblah- blah... yet those congruences, communities, earrings GOD damn all of it!!! as for that exponent stuff, once you experience like you should memorise formula and stuff by technique of coronary heart, take a deeep breath and... subtitute all them x's n y's with gool ol' shaped numbers. it is going to all make experience then and there. some astounding substitutions and also you'll get the patern and word that those regulations arent some thing that poped out of thin air ;) uhm... savour
2016-12-02 19:06:56
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answer #8
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answered by klosterman 4
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c^2 = a^2 + b^2
Sqrt(c^2) = Sqrt(a^2 + b^2) || Sqrt(c^2) = c
c = Sqrt(a^2 + b^2)
..so for a = 6 and b = 8 (or vice versa, doesn't matter)
c = Sqrt(6^2 + 8^2)
c = Sqrt(36 + 64)
c = Sqrt(100)
c = 10
2007-01-20 03:55:31
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answer #9
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answered by eva 3
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36 + 64 = c^2
100 = c^2
c=10(positive and negative)
2007-01-20 04:03:32
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answer #10
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answered by physicist05 2
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