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Im triying to use the distance for a problem and i have to finds what this is first and then find the square root of it.Please explain your answer and also what is the square root of 2ab?

2007-01-20 03:48:31 · 4 answers · asked by BENNETH[[98]] 2 in Science & Mathematics Mathematics

Whats (b-2a)^2 and then the square root of that?

2007-01-20 03:59:29 · update #1

show detail on how did you come up with the answer please

2007-01-20 04:00:02 · update #2

4 answers

(a + b - 0)^2

Note that the 0 does nothing to the equation, so it can effectively be ignored.

(a + b)^2

Expanding this,

a^2 + 2ab + b^2

As for what the square root of 2ab is, it can't be simplified *that* much, though if you wanted to, you can change it to this:

sqrt(2ab) = sqrt(2) [ab]

2007-01-20 03:52:33 · answer #1 · answered by Puggy 7 · 1 0

Ignore the 0:
(a+b)(a+b)
a^2+2ab+b^2

2007-01-20 12:46:21 · answer #2 · answered by Anonymous · 0 0

a+b-0=a+b so (a+b -0)^2 =(a+b)^2 = a^2 +2ab +b^2

The aqrt of 2ab is the sqrt of the product of 2*a*b

2007-01-20 11:56:31 · answer #3 · answered by santmann2002 7 · 2 0

(a+b-0)^2 = (a+b)^2 = (a^2) + 2ab + (b^2)

2007-01-20 12:05:35 · answer #4 · answered by physicist05 2 · 1 0

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