Here's the question:
Find the equation of the circle tangent to the x-axis with center (8, -3)
Please explain how you got your answer!! I have homework due by mindnight on sunday for class!
2007-01-20 03:39:28 · 3 answers · asked by mgunterksu 1 in Science & Mathematics ➔ Mathematics
Read your textbook.
2007-01-20 03:47:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The general equ.of circles with this center is(x-8)^2+(y+3)^2 =r^2
If the x axis is tangent thedistance from the center to this axis equals the radius.This distance is 3 absolute value of the ordinate of the center
(x-8)^2+(y+3)^2=9
2007-01-20 11:52:26 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
center(8,-3)
radius is the length between the points
(8,0) and (8,-3)
r=3
(x-8)^2+(y+3)^2=9
2007-01-20 11:45:12 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋