Find the magnitude of the following Vector: v= -2i - 4j ?
Trying to figure out how to set this type of problem up and answer it. Thanks for any help
2007-01-20 03:35:07 · 5 answers · asked by Matthew B 2 in Science & Mathematics ➔ Mathematics
The magnitude of a vector v is given by the following formula:
For v = (v1, v2)
||v|| = sqrt( (v1)^2 + (v2)^2) )
Therefore, since v = (-2, -4),
||v|| = sqrt ( (-2)^2 + (-4)^2 )
= sqrt (4 + 16)
= sqrt(20), which can be reduced to 2sqrt(5)
2007-01-20 03:40:00 · answer #1 · answered by Puggy 7 · 1⤊ 0⤋
magnitude of any vector expressed in 3componentS like
Xi + Yj +Zk is given by square root of (X^2+Y^2+Z^2)
hence here X= -2
Y= -4
Z= 0
so magnitude = square root of ((-2)^2+(-4)^2)
=square root of 20
= 2*square root of 5
2007-01-20 03:42:43 · answer #2 · answered by rajeev_iit2 3 · 0⤊ 0⤋
mod =sqrt( (4 +16)) = sqrt(20) In general
mod (ai+bj = sqrt((a^2+b^2))
2007-01-20 04:07:45 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
mag=sqrt[(-2)^2+(-4)^2]=sqrt(20)
always....
magnitude of x i - y j=sqrt[x^2+y^2]
2007-01-20 03:42:50 · answer #4 · answered by Tharu 3 · 0⤊ 0⤋
x=-2
y=-4
|v|=sqrt((-2)^2+(-4)^2)
=sqrt(4+16)
=sqrt(20)
=2sqrt(5)
2007-01-20 03:40:42 · answer #5 · answered by iyiogrenci 6 · 1⤊ 0⤋