In an election , the total turnout was 80% out of which 16% of the total voters on the voting list were declared invalid . What can be the % votes got by the winner of the election if the candidate who came 2'nd got 20% of the total voters on the voting list . {There were only 3 contestants , only one winner & the total no. of voters on the voting list was 20000 ..... Correct answer:anywhere between 20.01%-44% votes.HOW????
2007-01-19 23:34:34 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
80%-16% <-- invalid votes
64%
64% = number of votes that were counted
64 - 20% = 44%, -> which counts as the _maximum_ number of votes that could've went to the winner
since the 2nd guy got 20% which is 4,000 / 20,000 votes
it could mean the winner could've won by 1 vote (4,001 / 20,000) with 20.005% of votes (the _minimum_ % required for him to win)
(this is a rounded-off figure--->) 20.01% to 44% votes show the possible % of votes he received
anything above 20% and between 44%
2007-01-19 23:45:36 · answer #1 · answered by arcticcroc 4 · 0⤊ 0⤋
errm is this a question?
2016-05-24 00:19:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋