step by step answer?

Question

find value #%#11+%%# 2 , where # denotes reciprocal and % denotes square

Answer 1

#11 = 1/11
%#11 = (1/11)²
#%#11 = 1/(1/11)² = (11/1)² = 11²

#2 = 1/2
%#2 = (1/2)²
%%#2 = ((1/2)²)² = (1/2)⁴

11² + (1/2)⁴ = 121 + 1/16 = 121 1/16

If I understood the problem correctly.