how do you solve x(cube)-8=0? and what are the answers to this equation?

Answer 1

x = 2
2x2x2 - 8 = 0

to solve: x**3 - 8 = 0
x**3 = 8
cubed root of 8 = 2

-Dio

Answer 2

Solve > x^3 - 8 = 0

First: isolate x^3 on both sides > add "8" to both sides...

x^3 - 8 + 8 = 0 + 8

x^3 = 8

Sec: eliminate the exponent > find the cube root of both sides...

V`x^3 = V`8

V`(x*x*x) = V`(2*2*2)

x = 2

Answer 3

x^3 - 8 = 0
let f(x) = x^3 - 8
f(2) = 0, therefore (x - 2) is a factor

then, do (x^3 - 8) divided by (x - 2) by long division.
u will obtain (x^2 + 2x + 4).

(x^3 - 8) = (x^2 + 2x + 4)(x - 2) = 0

either (x^2 + 2x + 4) = 0 or (x - 2) = 0

(x^2 + 2x + 4) = 0-------[use formula and solve as complex number]
x = -1+i√2 and x = -1 -i√2

hence the solution to this equation are:
x = 2, x = -1+i√2 and x = -1 -i√2

Answer 4

x^3 - 8 = 0
or, x^3 - 2^3 = 0
This is a difference of two cubes, which can be factored as :

(x - 2)(x^2 + 2x + 4) = 0

Thus, either (x - 2) = 0, which implies x = 2

or, (x^2 + 2x + 4) = 0, which by the quadratic formula,
implies x = -1 + i*sqrt(3) or -1 - i*sqrt(3).

Answer 5

x^3-8=0 x^3=0+8 x^3=8 so x=the cube root of 8 which is 2x2x2= 8 x=2 let's check, yeah, that's it!

Answer 6

X^3-8=0
X^3=8
(X^3)^(1/3)=8^(1/3)
X=2

(the first - the second)(the first square - the first *the second + the second square)

where x: is the first and 2: is the second, and your life will become easy.

Answer 7

2 works

Answer 8

x^3 - 8 = 0
x^3 = 8
x^3 = 2^3
After Compare the base,
x = 2

Answer 9

x^3-8=0
x^3=8
Cube Root(x^3)=CubeRoot(8)
8 can be thought of as 2*2*2 or 2^3
Exponents cancel and the answer is 2.

Answer 10

x = 2

x(cube) - 8 = 0
transpose -8 to the other side of the equation
x(cube) = 8
get the cube root of both sides of the equation
cube root of x(cube) = cube root of 8
leaving you
x = 2