how do you solve x(cube)+1=0? and what are the answers to this equation?

Answer 1

x^3+1=0
=>x^3= -1
=>(x)^3=(-1)^3
=>x = -1

Answer 2

x^3+1=0
=>x^3= -1
=>(x)^3=(-1)^3
=>x = -1

Answer 3

x^3+1=0

solve: the goal is to find the value of x. First, we must eliminate the exponent of x which is 3. In order to do that, we will extract the cube roots of both sides.

cube root of x^3 = x
cube root of 1 = 1
cube root of 0 = 0

the equation will now be: x + 1 = 0

the equation is balanced. now, we solve for the value of x.
simply, we transpose 1 to the other side of the equation. And 1 will become negative. and now the answer will be:

x = -1

Answer 4

x^3 + 1 = 0

This is a sum of two cubes, which can be factored as :

(x + 1)(x^2 - x + 1) = 0

Thus, either (x + 1) = 0, which implies x = -1

or, (x^2 - x + 1) = 0, which by the quadratic formula,
implies x = (1/2) + i*sqrt(3)/2 or (1/2) - i*sqrt(3)/2.

Answer 5

x^3+1=0
====x+1 * x^2-x+1 =0&
x=-1 or x# {R}

HENCE X=-1

Answer 6

X^3-8=0
X^3=-1
(X^3)^(1/3)=-1^(1/3)
X=-1

(the first +the second)(the first square - the first *the second + the second square)

where x: is the first and -1: is the second, and your life will become easy.

(x-1)(X2+2X+1)

good luck