2007-01-19 17:56:15 · 4 answers · asked by Danny H 1 in Science & Mathematics ➔ Mathematics
For factoring polynomials,you should remember the following handy formulae
a^2+2ab+b^2=(a+b)^2
a^2-2ab+b^2=(a-b)^2
a^2-b^2=(a+b)(a-b)
a^3+b^3=(a+b)(a^2-ab+b^2)
a^3-b^3=(a-b)(a^+ab+b^2)
2007-01-19 18:04:24 · answer #1 · answered by alpha 7 · 1⤊ 0⤋
say the question is a(x square) +bx+ c
your trial solution would be (dx+e) where d is a factor of a and e is a factor of c
say the question is 3(x square) + 4x+1
so d could be 3, -3, 1, or -1 and e could be 1 or -1
your trial choice would be (3x+1), (x+1), (3x-1) etc obviously not all of them are going to work,
and then you just divide the polynomial by your trial solution, if you have no remainder, then it works.
same idea applies to higher orders.
hope this helps.
2007-01-20 02:05:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Yes, polynomials should be factored.
2007-01-20 02:00:07 · answer #3 · answered by Jim Burnell 6 · 0⤊ 0⤋
Thats more of a statement with a question mark....
2007-01-20 02:01:21 · answer #4 · answered by Pace 5 · 0⤊ 0⤋