A racket and 4 shuttlecocks cost $13. The racket costs $5.50 more than shuttlecock. Find cost of a shuttlecock

Answer 1

"A racket and 4 shuttlecocks cost $13."

r + 4s = $13

"The racket costs $5.50 more than shuttlecock."

r = s + $5.50

Substitute in the first equation:

(s + $5.50) + 4s = $13.00

5s = $7.50

s = $1.50

So a shuttlecock costs $1.50. And then, even tho the problem doesn't ask for it:

r = $1.50 + $5.50 = $7

A racket costs $7.

Answer 2

If all five pieces cost $13, then say that the r = racket and s = shuttlecock

So, r + 4s = 13
and, if the racket is $5.50 more than one shuttlecock,
then r = s + 5.5

Substitue the second equation into the first because it is already solved for one variable (r):
s + 5.5 + 4s = 13
5s + 5.5 = 13
5s = 13 - 5.5 = 7.5
s = 7.5 / 5 = 1.5

So, the shuttlecocks each cost $1.50 and the racket is $7.00

Answer 3

let r be the racket and s be the shuttlecock

r + 4s = 13
r = s + 5.5

(s + 5.50) + 4s = 13 (substitute)

5s + 5.50 = 13 (combine like terms)
- 5.50 -5.50

5s = 7.50
/5 /5 divide by 5 to get s by itself

s = $1.50

r = s + 5.50

r = 1.50 + 5.50
r = $7

shuttlecocks are $1.50 each($6 for 4) and the racket is $7, which would total $13.

Look in the index of your book under "Systems of Equations" or "Equations - Systems of", then look for "Substitution".

Answer 4

R+4S=13
R= S+5.50 so going to the first 5S +5.50=13 ==>5S = 7,50 and

S=1.50 R=7.00

Answer 5

let r=racket
s=shuttlecock

r+4s=13
r=5.50+s

(5.50+s)+4s=13
4s=13-(5.5+s)
4s=13-5.5-s
s+4s=13-5.5
5s=7.5
s=1.5

to check
r=5.5+s
r=5.5+1.5
r=7

r+4s=13
7+4(1.5)=13
7+6=13
13=13