Math work..........Help!!!!?

Question

okay..........I'm a older Brother ....Parent are away for the Three weeks. Have Two brother and a sister. I have been doing well so far....But, now I have to help one of my with his Math....It has been so long. I'm okay with math.....But, Not that Good!
I'm have problem with this ....Help!!! PLEASE!!!!!
1.(x-2)(x-3)=0
2.(x+3)(x+2)=x to the second power+5x+6
3.(x+3)(x-1)= x to the second power + 2x+3
4. (x-3)to the second power
5. (x-4)to the second power

PLEASE!

And........Show me how you got the answer in simple term......PLEASE!!!

Answer 1

1.
Seperate (x-2)=0 (x-3)=0
solve for x
x=2 , x=3

2. {EDITED, my mistake} You are correct

3. Use same steps as 2

4. (x-3)^2 = (x-3)(x-3)
Use FOIL
(x)(x)= x^2 , (x)(-3)= -3x , (-3)(x)= -3x , (-3)(-3)= 9

X^2 - 3x -3x +9
combine like terms
x^2 - 6x +9

To check you answer, Factor X
To get the number 9 we can either use 9x1=9 or 3x3=9
And to get -6 by adding two numbers, we can use -3 -3= -6
(x-3)(x-3) = (x-3)^2


5. use same steps as 4

Answer 2

1. As there are 2 terms whose product is zero, either can be zero. Hence x-2=0 or x-3=0. So x =2 or 3. Both answers satisfy the equation.
2.What you have stated is right.
3. The correct answer is x^2+2x-3.
4.(x-3)^2=x^2-6x+9.
5.(x-4)^2=z^2-8x+16.
For questions 4 and 5, the basic formula used is:(a+b)^2=
a^2+2ab+b^2.

Answer 3

1. x-2=0 x-3=0
x=2 or x=3

2 and 3 looked like they are already correctly solved... i'm confused

4. (x-3)^2 = x^2+9
5. (x-4)^2=x^2+16