A question about solids and equilibrium?

Question

Can you please explain the following:
The addition or removal of a substance in solid or liquid state does not change the concentration of that substance. The reaction of conndensed phases takes place only at an exposed surface- and if the surface exposed is changes it is always exactly the same chnage in available area for both forward and reverse reaction collisions. The forward and reverse rates will change by exactly the same amount if they change at all, so equilibrium is not disturbed and no shift occurs.

Answer 1

Your paragraph hardly sounds like English, but I will take a stab at it.

A reaction in Equilibrium is affected by certain changes, such as a change in concentration of one item, or a change in the temperature, and sometimes by a change in pressure.

However, a change in the surface area of a reactant, for example, grinding a chunk of solid to a powder, may cause the reaction to go faster, but it won't change the equilibrium. Because the increased surface area will speed up both the forward and reverse reactions equally. So the equilibrium is unchanged.

Answer 2

My first reaction might want to be that for a equipment at equilibrium (at the same time with the coolest ammonium chloride, that including extra ammonium chloride gained't impression the placement of the equilibrium. this signifies that the speed of the ahead and opposite reactions will stay a similar, and the equilibrium position gained't shift. including good ammonium chloride gained't shift the equilibrium, besides the undeniable fact that it would want to advance both the ahead and opposite prices through advance in floor portion of the coolest. With extra good the ahead fee will advance, yet because the equilibrium gained't shift, the opposite fee will journey the ahead fee in mild of the very incontrovertible reality that there is now a extra physically powerful floor section upon which the opposite reaction can take position. you're astounding, the placement of the equilibrium gained't substitute even as the coolest is better. If there's a substitute in the speed of reaction, then the ahead and opposite prices advance in share, and Keq is unchanged.