physics power problem?

Question

6. part1
A 1970 kg car accelerates uniformly from rest
to a speed of 17.3 m/s in 3.72 s.
Find the work done by the net force on the
car during this time interval Answer in units
of J.
part2
Find the average power delivered by the net
force to the car in this time interval. Answer
in units of w.
part3
What is the instantaneous power delivered by
the net force to the car at 2 s? Answer in
units of w.

Answer 1

Work=F*d

since a is uniform,
v=a*t
a=v/t
=17.3/3.72
=4.65 m/s^2

f=m*a
=1970*4.65
=9162 N

That was all very interesting, but the work is equal to the gain in kinetic energy

=1/2*m*v^2
=.5*1970*17.3^2
=294800 J

Pavg=work/time
=294800/3.72
=79247 W

Instantaneous power
P=F*V

at 2 s

v=a*t
v=2*4.65
=9.3

P=9162*9.3
=85206 W