A bicycle wheel has an initial angular velocity of 1.50 rad/s. a) if its angular acceleration is constant and equal to 0.300 rad/s^2.What is the angular velocity at t=2.50 s? b.) through what angle has the wheel turned between t=0 and 2.50 s ?
2007-01-19 13:42:36 · 6 answers · asked by jhen_hidaka 1 in Science & Mathematics ➔ Physics
when a particle is moving in circular motion, angular velocity is the velocity with which it covers a particular angular displacement is a given time.
angular vel = angular dispacement/time
in this ques
ini ang vel = 1.5 rad/sec
acc = 0.3 rad/sec^2
t = 2.5 sec
we'll apply the newton's first equation of motion
final vel = ini vel + acc*time
= 1.5 + 0.3*2.5
= 2.25 rad/sec
time = 2.5 sec
ini vel = 1.5 rad
final vel = 2,25 rad/sec
acc = 0.3 rads^2
applying the second equation of motion
dis = ini vel*time + 1/2*acc*time^2
= 3.75 + 0.9375
= 4.6875 rad
2007-01-19 13:59:55 · answer #1 · answered by aastha000 2 · 2⤊ 1⤋
Angular velocity = initial velocity + a * t = 1.50 + 0.300 * 2.50 = 2.25 rad/sec.
Angular displacement = 1/2 * a * t^2 = 0.150 * 6.25 = 0.9375 radians.
The same way you do linear displacement.
2007-01-19 22:23:43 · answer #2 · answered by hznfrst 6 · 0⤊ 0⤋
Rotational dynamics is JUST like linear dynamics. All the equations from the first few chapters of your physics book apply to rotational motion too!
Vf=at+Vo (Remember that equation?) Well
Wf=0.3(2.5) + 1.5 = 2.25 Rad/sec
Xf=(1/2)at^2 + Vot + Xo (Remember this equation?
THETAf=(1/2)(.3)(2.5)^2 + 1.5 (2.5) =
2007-01-27 21:15:55 · answer #3 · answered by Dennis H 4 · 0⤊ 0⤋
Wheel dia. X div. into 360 dgs. at Y rpm =AV (?)
The speed at which a wheel of known dia. divided into 360 equal parts and going Y inches per second/minute equals the distance of one degree line to the next degree line (time it takes to move through 1 degree of motion)
Don't laugh.
2007-01-19 23:33:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I'm not going to spell it out for you, but just treat this problem like you would any other linear problem. When it asks "through what angle has the wheel turn" it is asking for displacement.
2007-01-19 21:51:13 · answer #5 · answered by jayjoe 2 · 1⤊ 0⤋
aastha did too do it right! The initial speed has to be multiplied by the âtime and added to the distance caused by the acceleration. Her eq for dis is exactly right and substituted into correctly. She gets my vote!
2007-01-19 23:15:05 · answer #6 · answered by Steve 7 · 0⤊ 1⤋